A man standing infront of a mountain beats a drum at regular intervals. The drumming rate is gradually increased and he finds that the echo is not heard distinctly when the rate becomes 40 per minute. He then moves near to the mountain by 90m and finds that the echo is again not heard when the drumming rate becomes 60 per minute. If the distance (in meter) between the mountain and the initial position of the man is x, Find x/10.
Text Solution
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(27 m)
Time interval between beats (initially) = 
= 1.5 sec
Since t = 
1.5 = 
where S is the initial distance and v is the speed of sound. As the man approaches 90 m towards the mountain
= 1 since drumming rate is 60/min
Solving for S from the two relations we get
= 1.5
⇒ 3S – 3 × 90 = 2S
S = 270 m
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